Math 3210 Quiz #5 Fall 2009

Name _______________________________________________

(a) Write the equations for the transformation which consists of a rotation about the origin of 90o followed by a reflection about the line y = x.
(b) Write the equations for the inverse of this transformation.

Solution:
(a) The rotation about the origin by 90o is given by (x,y) -->(x',y'), where x' = -y and y' = x since Cos 90o = 0 and Sin 90o = 1. Reflection about y=x is given by (x',y')-->(x", y"), where x" = y' and y" = x'. So, the equations for the transformation (x,y)-->(x",y") are x" = x and y" = -y.
(b) The inverse of this reflection (which is itself) sends (x",y")-->(x,y) and so has equations given by x = x" and y = -y". Written as (x,y)-->(x''', y''') we would have x''' = x and y''' = -y.