Math 2000 - Solutions 6
Spring 2001
Unit 5A
6a. We use the compound interest formula for
compounding more than once a year. Setting P
= $1000, APR = 0.07, Y = 15, and n = 12 (for monthly compounding), the accumulated balance is
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8. With P = $500, APR = 0.045, and n = 12, the compound interest formula gives the following balance
after Y = 1 year.
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The annual yield is the percentage increase in the
balance in one year. We find that
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The account has increased its value by 4.6% in one
year.
20. Let’s look at the first five years. For
Bernard’s plan, we set P = $1600, APR = 0.04, n = 1, and Y = 5. The
accumulated balance is
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For Carla’s plan, we set P = $1400, APR = 0.05, n = 365, and Y = 5. The accumulated balance is
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Over a five-year period, Bernard has the better plan
because of his larger initial deposit.
How about a 20-year period? For Bernard’s plan, we
set P = $1600, APR = 0.04, n = 1, and Y = 20. The accumulated balance is
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For Carla’s plan, we set P = $1400, APR = 0.05, n = 365, and Y = 20. The accumulated balance is
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Over a 20-year period, Carla has the best plan,
because of the higher interest rate.
24 a. In this problem we must find the initial
deposit P that results in an
accumulated balance of $100,000. We have n
= 365 (daily compounding), Y =
18, and APR = 0.06. The initial
deposit P must satisfy
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We can solve this directly for P by dividing both sides of the equation by 2.9444. The required
initial deposit is
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An initial deposit of $33,963 is needed to
accumulate $100,000 in 18 years with daily compounding.
2. We use the savings plan formula and set PMT = $50, APR = 0.0825, n = 12
payments per year, and Y = 40 years
in the annuity formula. The accumulated balance at age 65 will be

The total amount deposited into the account over the
40-year period is
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Thus the IRA has earned about $160,000 in interest.
8. For George’s investment plan, we set PMT = $40, APR = 0.07, and n = 12
payments per year. The accumulated balance after Y = 10 years will be

George’s total payments are
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For Harvey’s investment plan, we set PMT = $150, APR = 0.075, and n = 4
payment per year. The accumulated balance after Y = 10 years will be

Harvey’s total payments amount to
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Harvey puts more money into his account and has a
slightly higher APR, so his
accumulated balance is higher after 10 years.