Math
2000 - Solutions 5
Spring 2001
6a.
0.00000002 = 2 ´ 10-8 (move
the decimal point 8 places to the right).
6e.
80 billion = 80,000,000,000= 80 × 109 = 8 ´ 1010 (move the decimal point 10 places to
the left).
10d.
2.3 ´ 106 =
2,300,000 (move the decimal point 6 places to the right).
10e.
2.2 ´ 10-4 =
0.00022 (move the decimal point 4 places to the left).
12d.
In 1995 the United States contributed $1.173 ´ 109 to international organizations.
14a.
(3 ´ 104) ´ (8 ´ 105) = (3 ´ 8) ´ (104 ´ 105) = 24 ´ 109 = 2.4 ´ 1010
14e.
(8 ´ 1012) ¸ (4 ´ 109) = (8 ¸ 4) ´ (1012 ¸ 109) = 2 ´ 103
18d.
Note that 7 trillion = 7 ´ 1012 and 7
thousand = 7 ´ 103.
Forming the quotient (7 ´ 1012 ) ¸ (7 ´ 103) = 109, we can say that 7 trillion is 109 or 1 billion times larger than 7 thousand.
22b.
There are several ways to proceed with this estimate. Some people could
estimate the amount a family spends for food more easily than the amount spent
by an individual for food. But let’s assume that a typical individual spends
$30 per week. Then that individual would spend
![]()
for
food. This estimate is also subject to considerable error due to the variation
in the amount spent per week.
29. The
conversion factor for the time-line is 100 (102) meters = 15 billion
(1.5 × 1010) years. To convert 1 billion (109) years to
meters, we us the conversion factor:
![]()
Similarly,
10,000 (104) years corresponds to
![]()
We see
that 1 billion years corresponds to 6.7 meters and 10,000 years corresponds to
about 0.067 millimeters.
37a.
Using a population figure of 280 million people, the daily per capita water use
can be found by dividing by the population:
![]()
37b.
Since public water comprises 10% of the total water use, the daily per capita
use of public water is 10% of the daily per capita use of total water (found in
the previous problem) which is 0.10 ´ 1.2 ´ 103 gallons per person per day = 1.2 ´ 102 gallons per person per day. On
average, each person uses 120 gallons of water per day!