Math 2000 Solutions 2
Fall 2001
10a.
The area of the floor is 40 yds × 25 yds = 1000 yd2. Notice how
multiplying two lengths with units of yards gives an area with units of square
yards. The volume of the cartons is 40 yds × 25 yds × 3 yds= 3000 yd3.
Notice how multiplying three lengths with units of yards gives a volume with
units of cubic yards.
12c. Begin with 4 weeks and use conversion factors to convert it to
units of minutes. Be sure that the units cancel appropriately:
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There are 40,320 minutes in 4 weeks.
14b. The first task is to find the conversion factor for cubic yards to
cubic inches. Following the procedure given in class, we begin with the fact
that 1 yd = 36 inches. Then we raise both sides of this relation to the third
power:
(1 yd)3 = (36 in)3
which implies that 1 yd3 = (36 × 36 × 36) in3 = 46,656 in3.
We see that 1 yd3 = 46,656 in3. We can now use
this conversion factor to convert 3 cubic yards to cubic inches:
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There are 139,968 cubic inches in 3 cubic yards.
16c. According to the conversion factor in Table 2.1, we see that 1
British pound = $1.51. To convert 75 pounds to dollars, we multiply by the
conversion factor in the appropriate form:
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We see that 75 British pounds is the same as $113.25.
36. We are given the conversion factor for acres to square feet. Thus,
¼ acre or 0.25 acre is equal to
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Thus, the lot has an area of 10,890 square feet. According to the
ordinance, a house may occupy at most ¼
of the lot, which is an area of ¼ × 10,890 square feet = 2722.5 ft2.
Unit 2B
6a. It’s easiest to relate both a deciliter and a milliliter to a
liter. According to Table 2.5, we have 1 liter = 10 deciliters and 1 liter =
1000 milliliters. We see that a deciliter is larger than a milliliter.
Furthermore, because 10 deciliters = 1000 milliliters, we know that 1 deciliter
is 100 times larger than 1 milliliter.
8b. We need the conversion factor for pounds to kilograms given in
Table 2.6: 1 kg = 2.2 lbs. Now we can do the conversion:
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There are 68.2 kilograms in 150 pounds.