a r
n = a
r n
If a n = r n then | a
n + 1 / a n | = r and
= r. The geometric
series converges if r < 1 and diverges if r > 1. These observations
led to two new convergence tests.
| r < 1 | implies | |
| r > 1 | implies | |
| r = 1 | implies | try another test |
1. Determine if
(-1) n 2 n / ( n ( 1 + 3 n )
) converges.
2. Determine if
(-1) n ( ln n ) / ( n! ) converges.
3. HOMEWORK #1: Determine if
n! / (3n)!
converges.
| r < 1 | implies | |
| r > 1 | implies | |
| r = 1 | implies | try another test |
4. Determine if
1 /
n n converges.
5. Determine if
(-1) n ( 1- 1 / n ) n converges.
6. HOMEWORK #2: Determine if
e - n
/ n converges.
Remark: Since both these test take the absolute value before the limit is taken, they test for absolute convergence. Remember that if a series is not absolutely convergent, it still can be conditionally convergent. For those series that are conditionally convergent, the limit in both the Ratio and Root test will be equal to 1 or the limit will not exist.
HOMEWORK ASSIGNMENT:
| REQUIRED PROBLEMS | #1, 2; Section 8.6: 2, 8, 14, 20, 22, 36, 38, 46 |
| SUGGESTED PROBLEMS | Section 8.6: 3, 13, 27, 29, 37, 43, 49, 51, 57, 59 |
Informative web sites:
READING ASSIGNMENT BEFORE NEXT WORKSHEET: Sections 8.7 and 8.8