In this first section, we will assign coordinates to the points of an
arbitrary affine plane in the following manner. Let
be an affine
plane. Choose any point, and name it 0. Using the proposition that
an affine plane has four points, and three are noncollinear, we know
that there exists three lines through our point 0 which are not
parallel (by axiom A1).
Let these three lines be named the x-axis, the y-axis, and the
diagonal. Choose a point on the diagonal different from 0 and
name it I. Let
be any abstract set with the same cardinality
as the number of points on the diagonal. Let two elements of
be 0 and 1. Now choose and fix a bijection
(points on
diagonal)
such that
and
. We will use the elements of
to be the coordinates of the points of
in the
following manner.
, let (a,a) be it's coordinate.
We can also describe the lines of the plane
by defining
slope and y-intercept. By A2 there exists the line
through the point I parallel to the y-axis. Let this line be the
line of slopes. Given any line l not parallel to the
y-axis, we know there exists a line parallel to it and through the point
0. This line intersects the line of slopes at a point (1,m). Assign
the slope m to l. The point at which l intersects the
y-axis is (0,b), and we call the y-intercept b. Note that the slope
of the diagonal is 1, the slope of the x-axis is 0, and we take the
slope of the y-axis and all other lines in its pencil to have undefined
slope. The slope and y-intercept uniquely determine the lines of
.
Figure 2: Slope and y-intercept
Given this coordinatization, we can define a ternary operation,
by the following.
Let l be a line with slope m and y-intercept b. Let s be a line
through (a,0) parallel to the y-axis. Define the point of
intersection of l and s to be (a,T(a,m,b)).
Notice that a point P with coordinates (x,y) lies on the line l if
and only if the equation
is satisfied.
Thus all lines have equations of the form
or x=a, a a
constant for lines parallel to the y-axis.